From the above algo the length of C is 0x68 bytes but from the log I have the cmd03 payload is 0x6C. What's going wrong ??
From the above algo the length of C is 0x68 bytes but from the log I have the cmd03 payload is 0x6C. What's going wrong ??
Unfortunately I have no access to the equipment you suggest. If you have such log you or someone else please send it to me.again.. you have log only from non original ci module.. try make loh from provider STB or CI module and decrypt all commands step by step and you will be see
maybe this is wrong "Data88=First 0x18 hex bytes are expanded using NNRSA idea expand which will generate 2 Prime numbers 0x34 bytes each"A doubt,
The pdf says "Data88 = First 0x18 hex bytes are expanded using NNRSA idea expand which will generate 2 Prime numbers 0x34 bytes each."
We know;
Data88 = FF4D54D984C85F83E0441945FC56B213243ABA7FBC24D05B 9D7EEE .......... 34F15CD99C269B83568114C
First_18 = FF4D54D984C85F83E0441945FC56B213243ABA7FBC24D05B
Can someone expand First_18 and show me the values of p_34 and q_34?
I got :
Data ..: ff4d54d984c85f83e0441945fc56b213243aba7fbc24d05b
p_34 ..: ae13323b0fdc712e9e7456c83ccf936fa68180eef7a047ea64ae70e4f5c31f75791979eb99c5d34222ae0b666c37010fe2588c3b
q_34 ..: dc136657d99d51ac4e34ee9df817986e7e9f569fe590c0908dc2289952809acf541dff85907bab37ac96a2bd250d65b5ca5f792d
p is not prime
q is not prime
But they are not correct because they are not primes.
I think that if we have only dt05_10 to the log then we have only generic pairing and the rsa68 is calculated according to pdf. If we had dt05_20 then we had to expand the 0x18 bytes of the unique rsa88 to 2 0x34 primes for the calculation of rsa68. Please tell if I am wrong.
I ask again my question I would like if possible to have some information on the rsa mod
thank you
3PO/vdr-plugin-sc"Data88=First 0x18 hex bytes are expanded using NNRSA idea expand which will generate 2 Prime numbers 0x30 bytes each"
Hi,
where i find information about NNRSA idea expand??
Thanks
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