Can you upload in megapictures
Dont know why you need BK and RSA!pictures
This picture is fake! dognaldo.
If they don't even know the difference between eCWs, dCWs eCWPK and dCWPKs as you can clearly see in the picture (CWPK00 and the dCW are the same) How the hell can you expect this to be true? And bruteforce takes years, It's not as easy as running a simple brute_des.exe tool. Forget It.
Maybe yes maybe no. Maybe i´m fake too.
Be a good observer. We have 4 bytes of the key ! What makes the process so much easier !
Stay with your truths and be happy.
Like I said, just for fun.
Actually you have 8 bytes (the key is 16) and you need the other 8, which still takes a very long time to bruteforce. And under normal circumstances you wouldn't have any bytes. The picture is also a photoshop because the initial key is only 8 bytes long... someone edited out the rest of the key... but even then this is worth nothing if you don't have the corresponding NUID.
If you have that brute_3des tool send us a link, but i'm guessing you don't either.
Again, try to be a good observer!
Look at the differences between des and 3des. Understand why 4 bytes.
If it were 8 bytes I would not waste time trying.
This is only the first step, NUID will only be used in the last step.
--> vvv.sat-universe.com/showthread.php?t=301544&page=6
Tdes:. SYSID 3411 = 6F XX 27 XX 9B XX 86 XX 6F XX 27 XX 9B XX 86 XX
(by onsitbin #748)
3Des_ecb decrypt
(Data = 16bytes, Key=16bytes (k1=k3))
data encrypt = BF 3F 84 D1 50 CA A3 99 09 AD F4 13 7B C7 5B 58
3Des decrypt Key = 6F 0E 27 3A 9B BC 86 F6 6F 0E 27 3A 9B BC 86 F6
data decrypt = 2A C9 F5 6A 35 B5 18 6D E5 E5 93 B0 BD B0 DA F2
Try with these 16 bytes (8 + 8) key´s too;
6F0E273A9BBC86F76F0E273A9BBC86F7
6F0E273A9BBD86F66F0E273A9BBD86F6
6F0E273A9BBD86F76F0E273A9BBD86F7
6F0E273B9BBC86F66F0E273B9BBC86F6
6F0E273B9BBC86F76F0E273B9BBC86F7
6F0E273B9BBD86F66F0E273B9BBD86F6
6F0E273B9BBD86F76F0E273B9BBD86F7
Des_ecb decrypt
(Data = 8bytes, Key=8bytes = k1)
data encrypt = BF 3F 84 D1 50 CA A3 99
Des decrypt Key = 6F 0E 27 3A 9B BC 86 F6
data decrypt = 2A C9 F5 6A 35 B5 18 6D
Try with these 8 bytes key´s too;
6F0E273A9BBC86F7
6F0E273A9BBD86F6
6F0E273A9BBD86F7
6F0E273B9BBC86F6
6F0E273B9BBC86F7
6F0E273B9BBD86F6
6F0E273B9BBD86F7
correct key ? Who knows !!!
[ ] ´s
Actually I know... it's not the correct key ..............
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